Coulomb potential barrier calculation and fm units

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 4K views
chemart
Messages
6
Reaction score
0
The Coulomb potential barrier of a system of two nuclei X and Y is approximately given by VC = ZX*ZY*e2/RN where ZX and ZY are the charge numbers of the nuclei, e2 = 1.44 MeV*fm, RN = (AX1/3+AY1/3) × r0 is the sum of the nuclear radii. r0 is a constant usually estimated to 1.2 to 1.3 fm and AX and AY are the mass numbers of the nuclei. Is this right calculation? What does fm stands for?
 
Physics news on Phys.org
It looks rlight. fm stands for femtometer (10^-15 meter).
The AX1/3 sands for AX to the one third power.