Derivative of dE=(kqz)/(z^2+R^2)^3/2 with respect to z

  • Context: Undergrad 
  • Thread starter Thread starter s7b
  • Start date Start date
  • Tags Tags
    Derivative
Click For Summary

Discussion Overview

The discussion revolves around finding the derivative of the expression dE=(kqz)/(z^2+R^2)^(3/2) with respect to the variable z. The context includes calculus techniques such as the quotient rule and chain rule, as well as challenges faced by participants in deriving the expression correctly.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant asks how to find the derivative of the given expression with respect to z, indicating that k and q are constants and R has a specific value.
  • Another participant suggests that the solution can be found by consulting a calculus textbook, implying that standard methods should suffice.
  • A different participant expresses frustration, stating that their attempts have resulted in a "huge mess" that seems incorrect.
  • Another reply mentions the use of the quotient rule and chain rule, suggesting that the final result can be expressed in two separate terms or combined under a common denominator.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct approach to finding the derivative, as there are differing levels of confidence and understanding expressed.

Contextual Notes

There is an indication of potential confusion regarding the application of calculus rules, and the discussion does not clarify specific mathematical steps or assumptions that may be necessary for resolving the derivative.

s7b
Messages
26
Reaction score
0
How would you find the derivative of;

dE=(kqz)/(z^2+R^2)^3/2 where k&q are constants and R=0.024 with respect to z??
 
Physics news on Phys.org
By reading your calculus textbook ...
 
I have but I end up with a huge mess that is definitely not right..
 
It's quotent rule and chain rule. Final result is two terms that can be left separate or taken under common denominator.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 0 ·
Replies
0
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K