Determine the value of the obscured digit

  • Thread starter Thread starter Math100
  • Start date Start date
  • Tags Tags
    Value
AI Thread Summary
The bank identification number is given as 237a4 18538, with a9 specified as 8. The congruence condition for a9 leads to the equation involving a4, resulting in the expression (5 + 7a4) mod 10. By solving the inequality derived from the congruence, it is determined that a4 must equal 9. Consequently, the obscured digit is confirmed to be 9.
Math100
Messages
813
Reaction score
229
Homework Statement
Consider the eight-digit bank identification number ## a_{1}a_{2}...a_{8} ##, which is followed by a ninth check digit ## a_{9} ## chosen to satisfy the congruence
## a_{9}\equiv (7a_{1}+3a_{2}+9a_{3}+7a_{4}+3a_{5}+9a_{6}+7a_{7}+3a_{8})\pmod {10} ##.
The bank identification number ## 237a_{4}18538 ## has an illegible fourth digit. Determine the value of the obscured digit.
Relevant Equations
None.
Consider the bank identification number ## 237a_{4}18538 ##.
Note that ## a_{9}=8 ##.
This means
\begin{align*}
&a_{9}\equiv (2\cdot 7+3\cdot 3+7\cdot 9+a_{4}\cdot 7+1\cdot 3+8\cdot 9+5\cdot 7+3\cdot 3)\pmod {10}\\
&\equiv (205+7a_{4})\pmod {10}\\
&\equiv (5+7a_{4})\pmod {10}.\\
\end{align*}
Since ## 3-7a_{4}=10k ## for some ## k\in\mathbb{Z} ## where ## 0\leq a_{4}\leq 9 ##,
it follows that ## -63\leq -7a_{4}\leq 0\implies -60\leq 3-7a_{4}\leq 3 ##.
Thus ## a_{4}=9 ##.
Therefore, the value of the obscured digit is ## 9 ##.
 
Last edited:
Physics news on Phys.org
Math100 said:
Homework Statement:: Consider the eight-digit bank identification number ## a_{1}a_{2}...a_{8} ##, which is followed by a ninth check digit ## a_{9} ## chosen to satisfy the congruence
## a_{9}\equiv (7a_{1}+3a_{2}+9a_{3}+7a_{4}+3a_{5}+9a_{6}+7a_{7}+3a_{8})\pmod {10} ##.
The bank identification number ## 237a_{4}18538 ## has an illegible fourth digit. Determine the value of the obscured digit.
Relevant Equations:: None.

Consider the bank identification number ## 237a_{4}18538 ##.
Note that ## a_{9}=8 ##.
This means
\begin{align*}
&a_{9}\equiv (2\cdot 7+3\cdot 3+7\cdot 9+a_{4}\cdot 7+1\cdot 3+8\cdot 9+5\cdot 7+3\cdot 3)\pmod {10}\\
&\equiv (205+7a_{4})\pmod {10}\\
&\equiv (5+7a_{4})\pmod {10}.\\
\end{align*}
Since ## 3-7a_{4}=10k ## for some ## k\in\mathbb{Z} ## where ## 0\leq a_{4}\leq 9 ##,
it follows that ## -63\leq -7a_{4}\leq 0\implies -60\leq 3-7a_{4}\leq 3 ##.
Thus ## a_{4}=9 ##.
Therefore, the value of the obscured digit is ## 9 ##.
Right.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...
Back
Top