Dextrose-based momentum-sensitive mixture

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SUMMARY

The discussion centers on the chemical behavior of a dextrose-based mixture involving 0.8 g of KOH, 30 ml of H2O, 1 g of dextrose, and methylene blue. The mixture exhibits a reversible color change from blue to transparent upon shaking, attributed to the redox reaction between dextrose and methylene blue. Methylene blue is reduced to leucomethylene blue (colorless) as it oxidizes dextrose, and shaking introduces oxygen, facilitating the regeneration of methylene blue. The presence of gluconic acid and its transformation to sodium gluconate are also noted as significant factors in the reaction.

PREREQUISITES
  • Understanding of redox reactions
  • Familiarity with the properties of dextrose and methylene blue
  • Knowledge of KOH and its role in chemical reactions
  • Basic concepts of oxidation states and their changes
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  • Research the mechanism of redox reactions involving aldehydes and methylene blue
  • Learn about the properties and reactions of gluconic acid and sodium gluconate
  • Explore the effects of oxygen introduction in chemical reactions
  • Investigate the role of shaking in accelerating chemical reactions
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Chemistry students, laboratory researchers, and anyone interested in the dynamics of redox reactions and colorimetric changes in chemical mixtures.

Weissritter
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O hai, PF
So, again, I come in the seek of help. I am usually good for my level on Chemistry, but this question was too hard for me.
In the lab, we added 0.8 g of KOH and 30 ml of H2O. Then, 1g of dextrose and methylene blue.
Final results were a liquid blue mixture. Thing is, when that thing is shaked, it changed to a transparent color. After resting, it became blue again. If shaked again, it would become transparent, then, after resting, blue again and ad infinitum.
Just why did this happen? What kind of reaction was happening?
As the final data I can give, the lab report says we could also have used glucose instead of dextrose. We were, also, studying redox reactions, I'd guess this one was redox, but what was it?

Was it K2O reacting to the dextrose? Was O2 changing its oxidation state by entering and leaving the compund depending on the momentum?
 
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The dextrose (glucose by another name) is an aldehyde that is oxidized by methylene blue. The methylene blue is reduced to leucomethylene blue (colorless) as it oxidizes the dextrose to ... what? The reaction stops there except you can do something to regenerate the methylene blue. What agent might be responsible for regenerating methylene blue from the colorless (actually light yellow, BTW) leucomethylene blue? How does shaking accelerate that reaction? Hint: it has nothing to do with momentum.
 
After some accidental searching, I found a name. Gluconic acid that can transform to sodium gluconate. I don't have the slightest idea of how those compounds are, but they do some weird magic.
No, no that kind of magic. I mean MAGIC, in capital and everything.
Now...what? I'm sure oxygen is part of the reaction, yet I'm clueless about how it is relevant.
 
You are right about oxygen - shaking the solution introduces the oxygen (which otherwise is present only close to the surface), allowing reactions to start.
 

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