Differentiation Help: Find dy/dx of y=4-1/x

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SUMMARY

The discussion centers on finding the derivative of the function y = 4 - 1/x. The correct differentiation process leads to the derivative y' = dy/dx = 1/x², not y' = 4 - x - 1 as initially stated. The confusion arose from misunderstanding the differentiation process and the notation dy/dx, which represents the derivative of y with respect to x. Clarification was provided that y' is indeed equivalent to dy/dx, and the correct approach involves applying the power rule and recognizing the form of the function.

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The riddler
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1. Hello everyone, my problem is with differentation. It seems to be quite simple but i can't understand it. Its basically find dy/dx of this equation:
y=4-1/x



2. The only relevant equation is dy/dx



3. I know how to differentate the equation to get y'=4-x-1 but i don't know how to get from there to dy/dx. To be honest I am not really sure what dy/dx is. I have been told the answer is dy/dx=x-2. Can someone please give me a clear explanation to what dy/dx means and explain to me how i get from the y' equation to dy/dx. Thanks for any replies :)
 
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first y'(x) is dy/dx, second y = 4 - x-1 to get to y' ie dy/dx you have to differentiate it but the only thing you did as I seen is rewrote y from 4-1/x to 4- x-1 that is not differentiation.
 
Don't worry i see where i was going wrong i understand now for some reason i thought Differentiate ment somthing else, thanks for replying anywayz
 

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