Graduate Dirac Notation: Why is order reversed in ket expasion?

Click For Summary
SUMMARY

The discussion centers on the reversal of order in the ket expansion of quantum states as presented in Shankar's "Principles of Quantum Mechanics" (2nd Edition). Specifically, it addresses the expression of the inner product and the outer product |i> PREREQUISITES

  • Familiarity with quantum mechanics concepts, particularly ket and bra notation.
  • Understanding of inner and outer products in Hilbert spaces.
  • Knowledge of operator non-commutativity in quantum mechanics.
  • Basic proficiency in mathematical summation and notation.
NEXT STEPS
  • Study the properties of Hilbert spaces in quantum mechanics.
  • Learn about the implications of operator non-commutativity in quantum systems.
  • Explore the significance of projection operators in quantum mechanics.
  • Review Shankar's "Principles of Quantum Mechanics" for deeper insights into ket and bra notation.
USEFUL FOR

Students and professionals in quantum mechanics, physicists working with Hilbert spaces, and anyone seeking to understand the intricacies of quantum state representation and operator notation.

RoadDog
Messages
7
Reaction score
2
TL;DR
When expanding a ket as a sum of components and basis unit vectors, Why is the order of ket and corresponding vector component reversed when writing the vector component as an inner product under the summation?
Shankar Prin. of QM 2nd Ed (and others) introduce the inner product:

<i|V> = vi ...(Shankar 1.3.4)

They expand the ket |V> as:

|V> = Σ vi|i>

|V> = Σ |i><i|V> ...(Shankar 1.3.5)

Why do they reverse the order of the component vi and the ket |i> when they write the former as the inner product <i|V>? It should not matter right? The reversal of order is almost as if it is to stress the appearance of the outer product |i><i|.
 
Physics news on Phys.org
Operationally one must be careful because the operators do not commute. This leads to complications better explained by those fluently conversant in Hilbert.
 
  • Haha
Likes kered rettop
Thank you for your reply. You are speaking of the outer product as the projection operator? Right. But I am asking, why must it be written as such. What is wrong with writing:

|V> = Σ <i|V> |i>

if <i|V> = vi?
 
Both ##v_i## and ##\bra i \ket v ## are numbers so their position does not really matter. It is a convention (a useful one) to leave the open operators on the outside.
 
Last edited:
OK thanks that is what I figured. Thanks
 
  • Like
Likes hutchphd

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
Replies
7
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K