Direction of impulse when object rebounds from surface

[isukatphysics69]

1. Homework Statement
In picture above

Homework Equations

impulse = Δp[/B]

The Attempt at a Solution

4.28NS = Δp
4.28NS = p_final - p_initial
4.28NS + 0.18kg*0.16m/s = p_final
(4.28NS + 0.18kg*0.16m/s)/.18kg = v_final
v_final = 39.77777778m/s

Now i got the direction incorrect but the magnitude correct. i am unsure of how i was supposed to
determine the direction. ?

 

[isukatphysics69]

NEVERMIND I FIGURED IT OUT!

 

[isukatphysics69]

The answer is -7.8m/s

 

[kuruman]

View attachment 224409
Now i got the direction incorrect but the magnitude correct. i am unsure of how i was supposed to
determine the direction. ?

Read the problem more carefully. The impulse is in the negative direction.