Discover How to Solve the x = y sin(x) Equation with Expert Tips

  • Context: Undergrad 
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Discussion Overview

The discussion revolves around the equation x = y sin(x), focusing on the challenges of finding a general formula for x. Participants explore the nature of solutions, including the lack of an analytic solution and the implications of the function's behavior.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested, Mathematical reasoning

Main Points Raised

  • One participant expresses difficulty in finding a general formula for x in the equation x = y sin(x).
  • Another participant asserts that there is no analytic solution for x and suggests using Newton's method or other approximation methods for accuracy.
  • Some participants note that the function mapping x to y = x/sin(x) is not one-to-one, indicating that there are infinitely many x values that yield the same y value.
  • Further elaboration on the function's non-injectivity is provided, emphasizing that it is not locally injective at many points.
  • A participant humorously reflects on the knowledge gap between those asking the original question and those familiar with concepts like injectivity.

Areas of Agreement / Disagreement

Participants generally agree that there is no analytic solution and that the function is not one-to-one, but the discussion includes varying levels of understanding regarding injectivity and the implications of this property.

Contextual Notes

Participants express uncertainty about the audience's familiarity with technical terms like injective and locally injective, which may limit the discussion's accessibility.

sid9221
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Hi,

I can't come up with a general formula for x in this equation. Any advice ?

x = y sin(x)
 
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There is no analytic solution for x. Your best bet is to use Newton's method or any other approximation method that will give you as much accuracy as you desire.
 
Beyond an analytic solution, there isn't a unique solution. The function [itex]\mathbb R\setminus \pi\mathbb Z \to \mathbb R[/itex] taking [itex]x\to y=\dfrac{x}{\sin x}[/itex] isn't one-to-one. In fact, there are infinitely many places at which very-close-but-different values of [itex]x[/itex] are taken to the exact same [itex]y[/itex] value.
 
Last edited:
economicsnerd said:
Beyond an analytic solution, there isn't a unique solution. The function [itex]\mathbb R\setminus \pi\mathbb Z \to \mathbb R[/itex] taking [itex]x\to y=\dfrac{x}{\sin x}[/itex] is very non-injective. There are infinitely many points at which it isn't even locally injective.

The intersection between those who would ask the OPs question and those who know who know what injective or locally injective must be null or a small number. A reasonable number that include me belong to neither class. :smile:
 
epenguin said:
The intersection between those who would ask the OPs question and those who know who know what injective or locally injective must be null or a small number. A reasonable number that include me belong to neither class. :smile:

You're right! I'll edit it (though my quoted mistake is immortalized in your post). :)
 

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