Divisibility by 9: Solving x+y+z Problems

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Homework Help Overview

The discussion revolves around a problem related to divisibility by 9, specifically concerning the expression x+y+z and its implications for other expressions involving x, y, and z. The original poster expresses confusion about how to approach such problems, particularly in a generalized context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants suggest reducing expressions modulo 9 and explore the implications of this approach. There are attempts to rewrite expressions in a form that highlights their divisibility by 9. Some participants question the understanding of modular arithmetic and its relevance to the problem.

Discussion Status

The discussion is ongoing, with participants providing insights into modular arithmetic and its application to the problem. Some guidance has been offered regarding rewriting expressions and understanding remainders, but there is no explicit consensus on the best approach or understanding of the topic.

Contextual Notes

There is uncertainty regarding the level of mathematical knowledge of the original poster, particularly concerning modular arithmetic and its application in the context of the problem. The problem is sourced from an SAT practice website, which may imply certain constraints on the methods expected to be used.

sh86
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This isn't a homework problem but I found it on the internet and can't figure out how to do it. It's one of those "divisible by whatever"-type problems which I never learned how to solve...

Given x, y and z such that x+y+z is divisible by 9, which of the following must also be divisible by 9?

a) 100x + 10y + z + 9
b) 10y + z + 9
c) 9x + 90y + z + 9
d) x + y + 9z + 9
e) 100x + 10y + 7z

I don't know how to work with this divisibility stuff when it's generalized to numbers like x+y+z. I don't even know where to begin. All I can do is "9w = x+y+z for some number w"...and now I don't know where to go. If I think up example values for x,y, and z I find that (a) keeps working, but I don't know why. Any help appreciated!
 
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Reduce the expression modulo 9.
 
I don't know what that means.. I don't think anything big is supposed to be used on this test since I found it on a SAT practice website.
 
Modular arithmetic isn't hard. It's fun! But alternatively, write a) as:

99*x+9*y+9+x+y+z

Now everything is divisible by 9, right?
 
100x + 10y + z + 9= 99x+ x+ 9y+ y+ z+ 9= 9(11x+ y+ 1)+ x+y+z
Does that answer the question for the first?

"reduce modulo 9" mean look for the part this isn't divisble by 9- the remainder when you divide by 9.

100= 9(11)+ 1 so 100 reduces to 1 modulo 9 and so 100x reduces to x modulo 9
10= 9+ 1 so 10 also reduces to 1 modulo 9 so 10y reduces to 7 modulo 9
Obviously 1 reduce to 1 modulo 9 so z reduces to z modulo 9
9 itself reduces to 0 modulo 9
In other words 100x+10y+z+ 9 consists of stuff that is obviously divisible by 9 plus x+ y+ z, the "modulo 9" part.
 
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in more layman terms, all you are doing is more or less finding remainders when dividing by 9. writing numbers N as N = 9d +r, where r is the remainder, d is some integer. For x+y+z, you have x+y+z = 9d +0. One thing you do not know from the question however is whether x,y,z are all individually divisible by 9. But if so, i guess that would make the question trivial given those 5 choices available.
 
I think he is trying to solve a problem from an SAT work book which includes trigonometric, algebraic and geometric arithmetic and not algebra (abstract algebra) so he might not be familar with the Modulo Arithmetic system? I had no idea what it was until I worked through a few chapters of a few different modern abstract algebra texts.

If he isn't, I don't know if he is going to understand it without a more clear definition, then again, I guess I can't make a judgment claim about a person I have never met. I have a slow learning curve so it might just be me.

Post number 10^2!

Sorry, I am bored at work.
 
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