Does an Elliptic Orbit's Speed Depend on Its Semi-Major Axis?

  • Thread starter Thread starter fahd
  • Start date Start date
Click For Summary
SUMMARY

The discussion centers on the relationship between the speeds of a particle in an elliptic orbit and its semi-major axis. It is established that the product of the maximum and minimum speeds is equal to [2πa/t]², where 'a' represents the semi-major axis and 't' is the orbital period. A participant questions whether the semi-minor axis 'b' should be used instead, but the consensus confirms that the semi-major axis is indeed correct. The derivation involves the area of the ellipse and the relationship between the period and the lengths of the axes.

PREREQUISITES
  • Understanding of elliptical orbits and central forces
  • Familiarity with the equations of motion in classical mechanics
  • Knowledge of the geometric properties of ellipses
  • Basic grasp of angular momentum and orbital mechanics
NEXT STEPS
  • Study the derivation of Kepler's laws of planetary motion
  • Learn about the conservation of angular momentum in orbital mechanics
  • Explore the mathematical properties of ellipses, including area and perimeter calculations
  • Investigate the relationship between semi-major and semi-minor axes in orbital dynamics
USEFUL FOR

Students and professionals in physics, particularly those focusing on celestial mechanics, orbital dynamics, and mathematical physics.

fahd
Messages
40
Reaction score
0
hi
i have this question to do which says..

*)A particle moves in a elliptic orbit under the influence of a central force F= -k/r^2.Prove that the product of the maximim and minimum speeds is equal to [2 pi a/t]^2 where 'a' is the semi major axis of the ellipse and 't' is the period of its motion..

Dont u think it should be the semi minor axis 'b' instead of the semi major axis 'a'..in the question..because I am getting the former as the right answer..
please help!
 
Physics news on Phys.org
wow. i have the exact same problem.
you can express the 'right answer' in terms of b
[tex]( \frac{2 \pi a} { \tau } )^2[/tex] eqs 1
recall:
[tex]\tau = \frac{2 A} {l}[/tex] eqs 2
where A is the area of an ellipse and is given by ╥ab
substituting 2 into 1 gives:
[tex]( \frac{2 \pi a} { \tau } )^2 = \frac{l^2} {b^2}[/tex]
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
9K
Replies
1
Views
4K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
2
Views
2K
Replies
7
Views
3K