# Does it matter which eigenvectors

1. Dec 10, 2012

### aaaa202

If you solve the Schrödinger equation time independent and find a number of stationary position states they are eigenstates. So say uou find the eigen state ψ then c*ψ is also an eigenstate, Does it matter which of these I pick as the eigenstate or is it only the eigenvalue that matters?

2. Dec 10, 2012

### The_Duck

We generally require our states to be normalized. This still lets you choose the overall complex phase of the state. You can take this phase to be anything you want, because the overall phase is not physical (i.e., not measurable).

3. Dec 10, 2012

### sugeet

By the First postulte of Quantum Mechanics, state is the most important thing, it contains all the information that can be known, eigen value will give you just the probablity, state is what we really intend to look for!!!!!

4. Dec 10, 2012

### Jorriss

Eigenvalues are what one can measure in experiments.

5. Dec 11, 2012

### sugeet

eigen value of a particular eigen state, its the probablity of the state!!!!!!!!!!!!!!!!!!!!!

6. Dec 11, 2012

### Jorriss

Are you thinking of expansion coefficients? The eigenvalues are not probabilities.