Does torque reduce/increase through gears?

  • Thread starter Thread starter PaulMa
  • Start date Start date
  • Tags Tags
    Gears Torque
Click For Summary
SUMMARY

The discussion focuses on the relationship between torque and gear ratios in a wind turbine system. A wind turbine rotor spinning at 16.7 RPM, connected to a gear with a 1:100.5 ratio, produces a power output of 2 MW with a final shaft speed of 1680 RPM. The torque at the main shaft is calculated using the formula T = (9549 * Power [kW]) / RPM, resulting in a torque of 11,367.86 Nm, which, when adjusted for the gear ratio, yields 1.142 MNm. The key takeaway is that torque increases through gear sets while power remains constant throughout the drivetrain.

PREREQUISITES
  • Understanding of torque calculations in mechanical systems
  • Familiarity with gear ratios and their impact on rotational speed
  • Knowledge of power transmission in drivetrain systems
  • Basic principles of wind turbine mechanics
NEXT STEPS
  • Research the formula P = T * omega for power and torque relationships
  • Explore the effects of gear ratios on torque and speed in mechanical systems
  • Learn about the dynamics of wind turbine design and efficiency
  • Investigate advanced torque calculation methods for complex gear systems
USEFUL FOR

Mechanical engineers, wind turbine designers, and anyone involved in power transmission and gear system analysis will benefit from this discussion.

PaulMa
Messages
1
Reaction score
0
Hi guys,

Great forum. I'm a frequent reader and first time poster.

I'm having a great deal of difficulty getting my head around something I have been researching.

If you have a wind turbine that is powered by wind (obviously) and causes the rotor with blades to spin at a constant 16.7rpm (which in turn turns the shaft), which is directly connected to a gear.

The gear is then connected to another gear and they have a 1:100.5 ratio. The power output is then 2MW (with the final shaft spinning at around 1680rpm).

How would you calculate the torque at the main shaft where the rotor is?

I came to this value, but I have no idea whether it's correct or not. It just seems like a lot for something that's only initially turning at 16.7rpm (by virtue of around 18m/s of wind).

Code:
Torque [Nm] = ( 9549 * Power [kW] ) / rpm

T = ( 9549 * 2000 ) / 1680 = 11367.86Nm

Then I multiplied 11367.86 * 100.5 (gear ratio) = 1.142MN

Any help would be appreciate to preserve my sanity!
 
Engineering news on Phys.org
Dear PaulMa

The key is to remember that power is constant throughout the drive train. Keeping this in mind together with the formula:

P = T * omega

shows you that when the power remains constant and the speed decreases, as is the case with the rotor of the wind turbine, then torque will increase.

As for your calculation, everything is correct. I checked from the point of view that the two gears are in equilibrium and this is where you can see that the torque increases through gear sets.

Regards
Janik Bessinger
 
Like janik.mech said, power is constant throughout the drivetrain, so it is much simpler to do:

T = ( 9549 * 2000 ) / 16.7 = 1.14 X 106 Nm = 1.14 MNm
 

Similar threads

Replies
2
Views
3K
  • · Replies 14 ·
Replies
14
Views
5K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
Replies
2
Views
4K
Replies
5
Views
3K
  • · Replies 18 ·
Replies
18
Views
8K
  • · Replies 18 ·
Replies
18
Views
11K
  • · Replies 7 ·
Replies
7
Views
3K