What Are the Key Characteristics of Henon Attractors?

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SUMMARY

The discussion focuses on the characteristics of Henon Attractors, specifically the Henon map defined by the equations x_{t+1} = a - x^2_{t} + by_{t} and y_{t+1} = x_{t}. Participants clarify the process of finding fixed points, noting that the fixed point occurs when x_{t+1}, x_{t}, and y_{t} are equal, leading to the quadratic equation -x^2_{b} + (b-1)x_{b} + a = 0. The inclusion of the term (b-1) is confirmed as necessary for solving the equation correctly. Additionally, the discussion addresses formatting issues in LaTeX for presenting equations.

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  • Understanding of Henon maps and chaotic systems
  • Familiarity with fixed point theory in dynamical systems
  • Basic proficiency in LaTeX for mathematical typesetting
  • Knowledge of quadratic equations and their solutions
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  • Study the properties of chaotic systems in the context of Henon Attractors
  • Learn about fixed point stability analysis in dynamical systems
  • Explore advanced LaTeX techniques for formatting mathematical equations
  • Investigate the implications of the Henon map in real-world applications
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Mathematicians, physicists, and students studying chaos theory, as well as anyone interested in the mathematical modeling of dynamical systems.

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1. Homework Statement

I am studying Henon Attractors. The Henon map is recursively defined as follows:

x_{t+1} = a - x^2_{t} + by_{t}<br /> y_{t+1} = x_{t}

I am supposed to find the fixed point (may be unstable) that is contained with the chaotic behavior

The Attempt at a Solution



It is clear that to find the fixed point would be when x_{t+1}, x_{t}, y_{t}
are all equal (Lets call them all x_{b}). It seemed obvious to just plug in
x_{b} and solve the quadratic, but the book had an extra term in the answer and I do not know where it came from:
-x^2_{b} + (b-1) x_{b} +a = 0. Where did the -1 in the b-1 term come from?
 
Last edited:
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If you just plug in x_b for x_t, y_t, and x_{t+1}, then the equation you get is exactly what the book says. Do your math again.
 
Oh, yes, the x_{b} on the left side is subtracted from the right to make it equal to 0. Duh!

Could you now how I insert a new line in the Latex equation? I can't seem to keep those two first equations from running together.
 
MathAmateur said:
Oh, yes, the x_{b} on the left side is subtracted from the right to make it equal to 0. Duh!

Could you now how I insert a new line in the Latex equation? I can't seem to keep those two first equations from running together.

The latex symbol for new line is \\
 
I did the following and got the following result:

x_{t+1} = a - x^2_{t} + by_{t} \\
y_{t+1} = x_{t}

x_{t+1} = a - x^2_{t} + by_{t}\\<br /> y_{t+1} = x_{t}
 

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