Find derivative of function with fractional exponent?

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SUMMARY

The derivative of the function R(t) = 5t^(-3/5) can be calculated using the power rule for derivatives. The power rule states that the derivative of t^α is αt^(α - 1) for any real number α. Applying this rule, the derivative is found to be -3t^(-8/5). It is important to express the exponent in fractional form rather than decimal notation for clarity.

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  • Familiarity with the power rule for differentiation
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coolbeans33
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I need to find the derivative of R(t)=5t-3/5

are there any derivative rules I can use for this problem?
 
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Re: find derivative of function with fractional exponent?

Welcome to MHB, coolbeans33! :)

coolbeans33 said:
I need to find the derivative of R(t)=5t-3/5

are there any derivative rules I can use for this problem?

Just the regular ones should do.
I presume you know that the derivative of $x^n$ is $nx^{n-1}$?
This is also true if n is a real number.
Or put otherwise: the derivative of $t^\alpha$ is $\alpha t^{\alpha - 1}$ for any real number $\alpha$.
 
Re: find derivative of function with fractional exponent?

so the answer is -3t-1.6?
 
Last edited:
Re: find derivative of function with fractional exponent?

coolbeans33 said:
so the answer is -3t-1.6?

Yes, although I would only use decimal notation if the exponent is given using such notation. In this case I would write:

$$\frac{d}{dt}\left(5t^{-\frac{3}{5}} \right)=5 \left(- \frac{3}{5} \right)t^{-\frac{3}{5}-1}=-3t^{-\frac{8}{5}}$$
 

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