MHB Find Difference in Total Cost for Engagement Ring at 2 Jewelers

Click For Summary
A prospective bridegroom compares engagement rings from two jewelers, each priced at $2400. The first jeweler requires a 20% down payment and charges 11% simple interest on the remaining balance, resulting in a total cost of $2611.20. The second jeweler requires a 25% down payment and charges 12% simple interest, leading to a total cost of $2616. The difference in total cost between the two jewelers is $4.80. Additionally, a customer inquires about the original amount of a bill that, with a 1.5% late fee, totals $332.92, and the correct original amount is calculated to be approximately $328.
bergausstein
Messages
191
Reaction score
0
1. A prospective bridegroom wants to buy an engagement
ring. Two jewelry stores each show him a ring at a cost
of \$2400. One jeweler requires a 20% down payment
with the balance to be paid at the end of one year at 11%
simple interest. The other jeweler requires a 25% down
payment with the balance to be paid at the end of one
year at 12% simple interest. What is the difference in
total cost?

my solution,

for the first jeweler

$.20(2400)=480$ \$480 down payment

$2400-480=1920$ \$1920 balance to be paid(with 11% interest)

then the total cost is,

$1920(.11)+1920+480=2611.2$

\$ 2611.2 total cost of the ring at the first jewelry store.

for the 2nd jewelry store,

$.25(2400)=600$ \$600 down payment

$2400-600=1800$ \$1800 balance to be paid(with 12% interest)

then the total cost is,

$1800(.12)+1800+600=2616$

\$ 2616 total cost of the ring at the 2nd jewelry store.

so, $2616-2611.2=4.8$ \$4.8 is the difference in the total cost.

did i get it correctly?

2. Because payment is one month overdue, a customer
receives a department store bill for \$332.92 that includes
a 1.5% interest charge for late payment. What was the
original amount of the bill?

my solution

$332.92-332.92(0.015)=327.9262$

\$327.9262 original price.

is this also right?

thanks!
 
Mathematics news on Phys.org
bergausstein said:
1. A prospective bridegroom wants to buy an engagement
ring. Two jewelry stores each show him a ring at a cost
of \$2400. One jeweler requires a 20% down payment
with the balance to be paid at the end of one year at 11%
simple interest. The other jeweler requires a 25% down
payment with the balance to be paid at the end of one
year at 12% simple interest. What is the difference in
total cost?

my solution,

for the first jeweler

$.20(2400)=480$ \$480 down payment

$2400-480=1920$ \$1920 balance to be paid(with 11% interest)

then the total cost is,

$1920(.11)+1920+480=2611.2$

\$ 2611.2 total cost of the ring at the first jewelry store.

for the 2nd jewelry store,

$.25(2400)=600$ \$600 down payment

$2400-600=1800$ \$1800 balance to be paid(with 12% interest)

then the total cost is,

$1800(.12)+1800+600=2616$

\$ 2616 total cost of the ring at the 2nd jewelry store.

so, $2616-2611.2=4.8$ \$4.8 is the difference in the total cost.

did i get it correctly?

Hello.

Yes.

bergausstein said:
2. Because payment is one month overdue, a customer
receives a department store bill for \$332.92 that includes
a 1.5% interest charge for late payment. What was the
original amount of the bill?

my solution

$332.92-332.92(0.015)=327.9262$

\$327.9262 original price.

is this also right?

thanks!

Not.

Supposing that 1,50 % is the total interest for the month of delay:

P=original price

P+\dfrac{1.5}{100} P=1.015 \ P=332.92

P=\dfrac{332.92}{1.015}=328Checking:

328+328 \dfrac{1.5}{100}=328+4.92=332.92

Regards.
 
Thread 'Erroneously  finding discrepancy in transpose rule'
Obviously, there is something elementary I am missing here. To form the transpose of a matrix, one exchanges rows and columns, so the transpose of a scalar, considered as (or isomorphic to) a one-entry matrix, should stay the same, including if the scalar is a complex number. On the other hand, in the isomorphism between the complex plane and the real plane, a complex number a+bi corresponds to a matrix in the real plane; taking the transpose we get which then corresponds to a-bi...