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Find the mass of Ag around the Nickel pole

  1. Nov 2, 2015 #1
    1. The problem statement, all variables and given/known data
    A nickel pole is put in an AgNO3 solution with volume 50ml and concentration 0.1 mol/litre until the concrentration is 0.02 mole/litre. Find the mass of Ag that is put around the Nickel pole.

    2. Relevant equations
    2AgNo3+Ni->Ni(NO3)2+2Ag
    number of moles= concrentration*volume
    n1=0.1*0.05=0.005 moles
    n2=0.02*0.05=0.001 moles.
    n1-n2=0.004 moles.
    So the numebr of Ag moles will be 0.004 too

    3. The attempt at a solution
    n1=0.1*0.05=0.005 moles
    n2=0.02*0.05=0.001 moles.
    n1-n2=0.004 moles.
    So the number of Ag moles will be 0.004 too
    Then m=0.004*108=0.432 moles. Am I right?
     
  2. jcsd
  3. Nov 2, 2015 #2

    Borek

    User Avatar

    Staff: Mentor

    Grams, not moles. Other than that what you did looks OK.
     
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