Find the nth Term of a Generating Function

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SUMMARY

The nth term of the series represented by the generating function f(x) = (Ʃ(k=1, to m-1) x^k) / (1-x^m) can be derived using the periodicity defined by m. For m=3, the series is 0, 1, 1, 0, 1, 1, 0, while for m=4, the series becomes 0, 1, 1, 1, 0, 1, 1, 1, 0. The general formula for the nth term can be expressed as n mod (m+1), where the output is determined by the periodic pattern established by m. This formula allows for the calculation of the nth term for any integer value of m.

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Emilijo
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If I know generating function of a series, what formula gives nth term?
Specifically, my generating function is f(x)=(Ʃ(k=1, to m-1) x^k)/(1-x^m)
***The function represent series: 0,1,1,...,1,0,1,1,...,1,0,...
where m is period; i.e. 0,1,1,0,1,1,0 m=3***
 
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generating function is f(x)=(sum_(k=1,to m-1) x^k)/(1-x^m), where m is period;
0,1,1,0,1,1... m=3
0,1,1,1,0,1,1,1,0... m=4...

What is nth term of the series given by the generating function?
Formula must be general, so I can just put m.
 

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