- #1

Cameron95

- 8

- 0

(u,v)= 4u1v1 + u1v2 + u2v1 + u2v2, where u=(1,0) v=(0,1)

(u,v)=|u|.|v|cosθ

1=(√4)cosθ

θ=∏/3

Surely the angle between the two vectors is ∏/2? I can't understand why it is ∏/3.