Finding Distance: Solve for Height from 1.77s Drop Time

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SUMMARY

The discussion revolves around calculating the height from which a golf ball was dropped, given a drop time of 1.77 seconds. The correct formula used is the distance formula: d = vit + 1/2 at², where vi is the initial velocity (0 m/s) and a is the acceleration due to gravity (9.8 m/s²). The calculated height is confirmed to be 15.35 meters, validating the approach taken by the participants in the discussion.

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Our class dropped a golf ball from an unknown height. The time it took for the golf ball to hit the ground was 1.77 seconds. We are now required to find the height from this information. I'd just like to run over the problem with you guys.

So:

t = 1.77s
vi = 0m/s
acc = 9.8 m/s^2 (Due to gravity, correct?)
d = ?

I'm suspecting that I use the distance formula of:

d= vit + 1/2 at^2

so that the height is:

15.35m?

---

I apologize for the simplicity of the problem, but I'd really appreciate help.
 
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yes, that's the right approach and the right solution
 

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