Finding k when 8√8 = 8^k

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[tex]8\sqrt{8}[/tex] can be written in the form [tex]8^{k}[/tex]

Find the value of k

I'm positive is a really easy question I though that k = 1/8, but that is wrong.
What is the method to answer this question.. I used trial and error and got k = 3/2, but what is the proper way?

Thanks
 
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Well what is a if [itex]\sqrt{8} = 8^{a}[/itex]?

What is b if [itex]8 = 8^{b}[/itex]?

What is [itex]8^a\cdot8^b[/itex]?
 
[tex]8^{\frac{2}{2}} x 8^{\frac{1}{2}}[/tex]

= [tex]8^{\frac{3}{2}}[/tex]

cheerz
 
thomas49th said:
[tex]8^{\frac{2}{2}} x 8^{\frac{1}{2}}[/tex]

= [tex]8^{\frac{3}{2}}[/tex]

cheerz
Pleasure :smile: