Finding the Angle Between Two Charged Spheres Using Coulomb's Law

  • Thread starter seto6
  • Start date
  • Tags Tags
    Force
1 reply · 20K views · last reply
seto6
Messages
248
Reaction score
0

Homework Statement



The figure shows two 5.0 g spheres suspended from 1.0-m-long threads. The spheres repel each other after being charged to +31 nC. What is the angle θ ?
Diagram of two spheres hanging from a common support on 1.0 m threads, each sphere labeled 5.0 g, with the half-angle theta marked between each thread and the vertical dashed line.



Homework Equations



Coulomb's law equation written as F = k_e q1 q2 / r^2, with F, k_e, q1, q2 and r as symbols.



The Attempt at a Solution



i tried it by writing equation in the x and y component for one of the ball and then i would have two unknowns tension and the radius.

now for sin (theta) = r/1
cos (theta) = sqrt(1-r^2)

so for the columbs force the radius would be 2r.

now i solved for r = 4.4108*10^(-5)

this doesn't make sense, i would get the angle to be 2.53*10^(-3)

but the choice for the angles are :
Multiple-choice answer list with four radio buttons: 3.0 degrees, 1.4 degrees, 2.2 degrees, 2.0 degrees.


Thanks for helping
 
It T is the tension in the string, then
Tsinθ = F

Tcosθ = mg

tanθ = 9*10^9*(31*10^-9)^2/r^2*5*10^-3*9.8

Since θ is very small, tanθ is nearly equal to θ = r

So r^3 = (θ)^3 = 9*10^9*(31*10^-9)^2/5*10^-3*9.8

Now solve to find θ.