Finding the Smallest n for F(n)=24: A Challenge in Integer Solutions

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SUMMARY

The discussion centers on determining the smallest integer n for which the function F(n) equals 24, specifically in the context of integer solutions involving sums of squares. It is established that F(n) represents the total number of integer solutions for a given n. The participants clarify that there are no solutions for two squares summing to 24, while three squares can yield solutions such as 4² + 2² + 2². Additionally, six squares can be represented as 2² + 2² + 2² + 2² + 2² + 2², leading to the conclusion that n=6 is a valid candidate.

PREREQUISITES
  • Understanding of integer solutions in number theory
  • Familiarity with sums of squares
  • Knowledge of mathematical functions and their properties
  • Basic problem-solving skills in algebra
NEXT STEPS
  • Research the properties of sums of squares in number theory
  • Explore the function F(n) and its applications in combinatorial mathematics
  • Learn about the Lagrange's Four Square Theorem
  • Investigate methods for finding integer solutions to polynomial equations
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Mathematicians, students studying number theory, educators teaching algebra, and anyone interested in solving integer equations involving sums of squares.

pi_kid
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I'm having some trouble with a particular question brought up in class. It says given F(n)= to the total # of integer solutions what is the smallest n such that F(n)=24. I know how to find F(n) given n, but i can't figure out how to work backwards. Any hints would help.
 
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"integer solutions" to what?
 
By sums of squares it depends on the amount of terms your adding. There is no answer for 2 squares to equal 24 but for 3 squares there's 4^2+2^2+2^2 and then for 6 squares it could be 2^2+2^2+2^2+2^2+2^2+2^2 so i would guess 2? Please fully explain the problem though.
 

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