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Finding where the plane intersects the x,y,z axes

  1. Jul 21, 2007 #1
    1. The problem statement, all variables and given/known data
    The plane defined by x + 2y + 3z = 12 and the point P(4,6,8)
    Find where the plane intersects the x,y and z axes

    2. Relevant equations



    3. The attempt at a solution
    I don't know where to start, I can vaugely remember that the variable t is brought into the equation, but im really stuck. Your help is appreciated.
     
  2. jcsd
  3. Jul 21, 2007 #2

    Dick

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    If a point (x,y,z) is on, e.g. the x-axis, what are y and z?
     
  4. Jul 21, 2007 #3

    Dick

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    Oh, yeah, and your point P is NOT on the plane. Do you want the plane parallel to the given one and passing through P? Reread the question.
     
  5. Jul 21, 2007 #4
    You can try to get the equation in the intercept form [tex]x/a+y/b+z/c=1[/tex] where (a,0,0) (0,b,0) and (0,0,c) are the intercepts on the x, y, and z axes. HINT: Divide by 12.
     
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