- #1
Kavorka
- 95
- 0
There is a specific step when solving first-order equations introduced in my textbook when describing the process for solving with an integrating factor, and it has been popping up everywhere - I do not understand how it works and the book doesn't explain it well.
Example 1:
x(dy/dx) + y = sin(x) / x
becomes
d/dx(xy) = sin(x) / x
Example 2:
e^-x (dy/dx) - y(e^-x) = e^(-4x/3)
becomes
d/dx(y(e^-x)) = e^(-4x/3)I'm having trouble rationalizing how this step is performed. Thanks for any help!
Example 1:
x(dy/dx) + y = sin(x) / x
becomes
d/dx(xy) = sin(x) / x
Example 2:
e^-x (dy/dx) - y(e^-x) = e^(-4x/3)
becomes
d/dx(y(e^-x)) = e^(-4x/3)I'm having trouble rationalizing how this step is performed. Thanks for any help!