Force of impact when dropping an object on the floor

  • Thread starter Thread starter fog37
  • Start date Start date
  • Tags Tags
    Force Impact
Click For Summary
When an object is dropped, the force of impact varies with time and distance as it comes to rest upon hitting the ground. To calculate the impact force of a metal dumbbell on a concrete floor, one needs to know the time or distance over which the object is decelerated, as the collision is inelastic and energy is converted to heat. Measuring the impact force accurately is complex, and using accelerometers may not yield reliable results unless they are rated for high G-forces. Conducting simple experiments, such as dropping the dumbbell on different surfaces, can provide rough estimates of peak force based on the resulting damage. Overall, practical experimentation may offer more accurate insights than theoretical calculations in this scenario.
fog37
Messages
1,566
Reaction score
108
Hello,

I understand that when we drop an object from a certain height on the floor, there is a force of impact (action reaction) once the object reaches the ground. I can easily calculate the final speed of the dropped object before the impact but I need to know either the time or the distance over which the dropped object is brought to rest by the floor to determine the force of impact.

If a metal dumbbell was dropped on a concrete floor, how could I determine the impact force? The collision is clearly inelastic since the dumbbell does not bounce back up. All the kinetic energy is converted into heat of the floor and dumbbell. The coefficient of restitution of the two materials would be zero. How can I know how much the concrete floor and dumbbell deform?

Thanks
 
Engineering news on Phys.org
fog37 said:
I understand that when we drop an object from a certain height on the floor, there is a force of impact (action reaction) once the object reaches the ground.
It isn't "a" force in the sense of being a constant force. It would vary with distance and time.

I can easily calculate the final speed of the dropped object before the impact but I need to know either the time or the distance over which the dropped object is brought to rest by the floor to determine the force of impact.
That would allow you calculate an average force with respect to distance or an average force with respect to time, but the numerical value of the two averages need not be the same. If you are trying to compute a single numerical value of force, what would you use that numerical value for? For example, if you were trying to design a floor to resist the impact of a dumbbell, you might have to worry about the maximum force , not just the average force.
 
Thanks Stephen Tashi,
I can see how the force of impact would vary and it would be sensible to compute the max force. But given the change in momentum, the force is F= Delta_v / Delta_t which means I need the time of impact (or the distance of impact)...How do I get to that for materials like concrete and steel?
 
Short answer is that you can't. Even a rough estimate is difficult because the system is too complex to analyze using hand calculations. I do know that attempting to measure a similar impact with a 50G accelerometer will not work, and a 500G accelerometer might work. But don't count on it.

You could try some simple experiments. Drop a dumbbell on the floor or on an object such as a penny. Does the floor dent the dumbbell? Does the dumbbell chip the floor or dent the penny? If so, you can estimate peak force from the size of the damage and material properties. Such an estimate, while rough, will be more accurate than a theoretical calculation.
 
  • Like
Likes Dr.D
JRMichler said:
I do know that attempting to measure a similar impact with a 50G accelerometer will not work, and a 500G accelerometer might work.
Mostly out of curiosity... how do you happen to know this?
 
Short answer: BTDT.

Slightly longer answer: I've done a lot of work with measuring dynamic phenomena: forces, stresses, vibrations, speed, acceleration. I don't have a good example of an impact that saturated a 500 G accelerometer, but the figure below is an interesting example of just how large impact forces can be. It's from US Patent Application 20130184139. You can look up the application at patft.uspto.gov. Click on Number Search under AppFT: Applications, then enter the number. Part 102 is about 3/16" thick, slightly over 1" wide, about 2" long, and made of steel. Part 106 was made from Nylatron. Spring 104 is about the size and stiffness of a ball point pen spring. In use, part 102 is pushed down about 1/16", then released. The spring pushes it outward until part 102 hits the stops at 120 and 122. That impact broke pins 108 and 110. We were able to observe the impact using high speed video at 10,000 frames per second, and measure the impact velocity and duration. From that, and assuming elastic impact, the peak impact force was calculated at slightly over 100 lbs. Some FEA work with part 106 showed stresses that completely explained the failures.

upload_2017-10-6_8-21-4.png
 
Had my central air system checked when it sortta wasn't working. I guess I hadn't replaced the filter. Guy suggested I might want to get a UV filter accessory. He said it would "kill bugs and particulates". I know UV can kill the former, not sure how he thinks it's gonna murder the latter. Now I'm finding out there's more than one type of UV filter: one for the air flow and one for the coil. He was suggesting we might get one for the air flow, but now we'll have to change the bulb...

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
11
Views
4K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
14
Views
4K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K