Force Problem: Calculating Ground Force on Jumping Boy with Stiff-Legged Landing

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The discussion focuses on calculating the ground force exerted on a boy weighing 400 N who jumps from a height of 2.00 m and lands stiff-legged. The force of the ground on his feet is determined to be 40,400 N, factoring in a constant force during landing and negligible compression of tissue and bones. The calculation uses the formula F = (weight/acceleration due to gravity)(gravity) + weight, confirming the final answer of 40,400 N. The user also briefly considers the work-energy principle but resolves the problem without it.

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Miike012
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A boy weighing 4.00 *10^2 N jumps from a height of
2.00 m to the ground below. Assume that the force of the
ground on his feet is constant.
Compute the force of the ground on his feet if he
jumps stiff-legged, the ground compresses 2.00 cm,
and the compression of tissue and bones is negligible

solution:

F = (4.00*10^2/9.8)(9.8) + (4.00*10^2) = 800
answer is 4.04 *10^4 N
 
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Could I use the formula

Wnc = ΔE ?
 
Nevermind I got it
 

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