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91. Write balanced equations to show the formation of each of the following compounds. Name the reactants in each case, and show clearly the removal of the water molecule.
a) butyl propanoate
b) propyl methanoate
Answers:
a) butyl propanoate- C7H14O2 = (CH3CH2COOCH2CH2CH2CH3)
C2H5COOH + C4H9OH ---> C7H14O2 + H2O
Propanoic acid + Butanol ---> butyl propanoate + water
b) propyl methanoate - C4H8O2 = (HCOOCH[SIZE="1"]2CH[SIZE="1"]2CH[SIZE="1"]3)
C[SIZE="1"]3H[SIZE="1"]7OH + HCOOH ---> C[SIZE="1"]4H[SIZE="1"]8O[SIZE="1"]2 + H[SIZE="1"]2O
Propanol + methanoic acid ---> propyl methanoate + water
[B]The equations are both balanced right now with the water molecules, but how do I show the removal of the water molecule and make them balanced again?[/B]
a) butyl propanoate
b) propyl methanoate
Answers:
a) butyl propanoate- C7H14O2 = (CH3CH2COOCH2CH2CH2CH3)
C2H5COOH + C4H9OH ---> C7H14O2 + H2O
Propanoic acid + Butanol ---> butyl propanoate + water
b) propyl methanoate - C4H8O2 = (HCOOCH[SIZE="1"]2CH[SIZE="1"]2CH[SIZE="1"]3)
C[SIZE="1"]3H[SIZE="1"]7OH + HCOOH ---> C[SIZE="1"]4H[SIZE="1"]8O[SIZE="1"]2 + H[SIZE="1"]2O
Propanol + methanoic acid ---> propyl methanoate + water
[B]The equations are both balanced right now with the water molecules, but how do I show the removal of the water molecule and make them balanced again?[/B]