Undergrad Free Schroedinger equation: time separation

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The discussion focuses on the interpretation of solutions to the free Schrödinger equation, specifically regarding the time-dependent part e^{±iωt}. The original poster questions why e^{+iωt} leads to a different equation than expected, while others clarify that both e^{+iωt} and e^{−iωt} correspond to positive energy solutions when considering complex conjugates. It is emphasized that for a free particle, both solutions represent valid physical states with positive energies. The distinction between the wave functions and their complex conjugates is noted as significant in quantum field theory, where they relate to particles and antiparticles. Understanding these relationships is crucial for grasping the underlying physics of quantum mechanics.
chartery
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Hi

Apologies for formatting, I can't get PF's new Tex to work for me.

The (?most) general solution of the free Schroedinger eq. is e^{±i(kx-ωt)} , which implies e^{+iωt} should solve the time separated ODE:
dψ/dt = -iωψ, but instead it satisfies dψ/dt = +iωψ which is not obviously (to me) the same equation. Could someone explain where my logic errs please?
 
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chartery said:
Hi

Apologies for formatting, I can't get PF's new Tex to work for me.

The (?most) general solution of the free Schroedinger eq. is e^{±i(kx-ωt)} , which implies e^{+iωt} should solve the time separated ODE:
dψ/dt = -iωψ, but instead it satisfies dψ/dt = +iωψ which is not obviously (to me) the same equation. Could someone explain where my logic errs please?
Because the energy ##E=\hbar \omega## is supposed to be positive, physically speaking (up to an additive constant).
Insert ##\psi (x,t)=e^{\pm i\omega t}\psi(x)## in Schrödinger's equation and see what happens.
 
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@pines-demon, thanks for reply. If I plug in e+iωt , I get separation constant as -ħω. Does that mean it is a "negative energy" solution?
 
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chartery said:
If I plug in e+iωt , I get separation constant as -ħω. Does that mean it is a "negative energy" solution?
Note that the wave functions in the Schrödinger equation are complex functions.

##e^{-\mathrm{i}\omega t}## corresponds to the positive-energy solution.

##e^{+\mathrm{i}\omega t}=\left(e^{-\mathrm{i}\omega t}\right)^*## then corresponds to complex conjugate of the positive-energy solution.

For a free particle, both "##\pm##" solutions correspond to positive energies, its just that you use both the "normal" wave function ##\psi## and the complex-conjugated wave function ##\psi^*##.

This plays a role in quantum field theory, where ##\psi##'s correspond to wave functions of particles and ##\psi^*##'s - to wave functions of their anti-particles. Both the particle and its anti-particle are physical and have positive energies; the difference is that one of the wave functions is a complex-conjugated version.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA

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