Oakwater
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Homework Statement
Given for polystyrene K = 1.6x10^5 and a = 0.71
and for PVC K = 1.5x10^5 and a = 0.77
a universal calibration curve has been created from PS and the molar mass of PVC at a certain elution volume has been calculated.
The part I'm not sure on is the question:
Show which of the two polymers is more compatible with tetrahydrofuran (THF).
Homework Equations
[η]= KM\stackrel{a}{v}
[η]_{x} M_{x} = [η]_{PS} M_{PS}
K_{x} M\stackrel{ax +1}{x} = K_{PS} M\stackrel{aps +1}{PS}
The Attempt at a Solution
From my understanding the constant "a" in the equation is related to the polymer - solvent interaction, in that the higher the value of a, the more compatible with the solvent the polymer is.
Also for the molar mass of PVC compared to PS at a given elution volume the molar mass is lower than that of PS, is this relevant? as a increases the molar mass continues to drop and at lower a values the molar mass rises. Am I correct in thinking that a greater molar mass at a given elution volume means that there is less compatibility between the polymer and the solvent?
Essentially, am I on the right lines here as I have done considerable searching but cannot find anywhere that explicitly links the constant "a" with compatibility or a study on a link between molar mass at elution volumes to compatibility.
I apologise if my equations are not completely clear.
Thanks