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## Homework Statement

Given for polystyrene K = 1.6x10^5 and a = 0.71

and for PVC K = 1.5x10^5 and a = 0.77

a universal calibration curve has been created from PS and the molar mass of PVC at a certain elution volume has been calculated.

The part I'm not sure on is the question:

Show which of the two polymers is more compatible with tetrahydrofuran (THF).

## Homework Equations

[η]= KM[itex]\stackrel{a}{v}[/itex]

[η][itex]_{x}[/itex] M[itex]_{x}[/itex] = [η][itex]_{PS}[/itex] M[itex]_{PS}[/itex]

K[itex]_{x}[/itex] M[itex]\stackrel{ax +1}{x}[/itex] = K[itex]_{PS}[/itex] M[itex]\stackrel{aps +1}{PS}[/itex]

## The Attempt at a Solution

From my understanding the constant "a" in the equation is related to the polymer - solvent interaction, in that the higher the value of a, the more compatible with the solvent the polymer is.

Also for the molar mass of PVC compared to PS at a given elution volume the molar mass is lower than that of PS, is this relevant? as a increases the molar mass continues to drop and at lower a values the molar mass rises. Am I correct in thinking that a greater molar mass at a given elution volume means that there is less compatibility between the polymer and the solvent?

Essentially, am I on the right lines here as I have done considerable searching but cannot find anywhere that explicitly links the constant "a" with compatibility or a study on a link between molar mass at elution volumes to compatibility.

I apologise if my equations are not completely clear.

Thanks