A Hamiltonian in an electromagnetic field

Tags:
1. Dec 3, 2017

2. Dec 3, 2017

stevendaryl

Staff Emeritus
The second equation just mathematically follows from the first equation by taking complex conjugates. If $\psi$ is any complex-valued function, and $\vec{A}$ is any real vector-valued function, then $[(-i\hbar \vec{\nabla} - e \vec{A})^2 \psi]^* = (+i \hbar \vec{\nabla} - e \vec{A})^2 \psi^*$

Self-adjoint doesn't mean that $H = H^*$. It means that $\int \phi^*(\vec{x}) (H \psi(\vec{x})) d^3x = \int (H \phi(\vec{x}))^* \psi(\vec{x}) d^3x$