Headlight Effect: Finding $\phi_0$ on Earth

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SUMMARY

The discussion centers on finding the angle \(\phi_0\) on Earth using the headlight effect, specifically through the equation \( \cos(\phi) = \frac{(\cos(\phi') + \frac{u}{c})}{(1 + \frac{u \cdot \cos(\phi')}{c})} \). The original poster, an engineer, initially sought assistance but later confirmed they resolved the issue independently. No additional equations for headlight effects were identified in their resources.

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James T. Kirk twice bluffed that the USS Enterprise was equipped twith a corbomite devise that automatically sends a pulse of energy that equals the force put on it. But that's besides the point :P

I have a problem that asks me to find \phi_0 on Earth via headlight effect.

I already have found the equation:
cos(\phi) = (cos(\phi')+ u/c) / (1 + (u* cos(\phi')/c))

Do I simply solve for \phi as \phi_0, or is there some equation for headlight effects? My book and my notes only have a mention of headlight effect, that I can find.
 
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I'm an Engineer not a Doctor!

Okay, I figured it out.

NO HELP NEEDED NOMORES!
 

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