Help with vectors

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Hand-drawn force diagram with x and y axes meeting at the origin. Three red arrows: 100 N up and to the right at 30 degrees above the horizontal, 300 N down and to the left at 60 degrees, and 700 N down and to the right at 45 degrees below the vertical. Teal handwritten note reads: slove the problem as showm in fig...


-__- aah please help
 
SFOo said:
find the Rx and Ry

And why are you stuck on this problem? Where is your attempt at a solution?
 
were not a free homework service... its really not a hard question, do some research
 
Vx = V cos [tex]\theta[/tex]
Vy = V sin [tex]\theta[/tex]
 
iRaid said:
Vx = V cos [tex]\theta[/tex]
Vy = V sin [tex]\theta[/tex]

thanx
but can u show me how did u do it :) please
 
SFOo said:
thanx
but can u show me how did u do it :) please

Go back to your book or notes. This is really basic stuff; every book has an example that will be able to help you. You might even want to go back and review what a vector is, as you seem to be quite lost.

As stated in the rules, we are not going to do your work for you. If you care to take a stab at the problem (and depending on how honest of an attempt it is) we may offer corrections to help you understand.
 
lets go back to Trig 101, take a look
[PLAIN]http://img547.imageshack.us/img547/1426/vectors.png

sin([tex]\theta[/tex]) = Opp/Hyp
cos([tex]\theta[/tex]) = adj/Hyp

So if you look at the picture above, if you want the Y component you get

sin([tex]\theta[/tex]) = Vy/V // just replace Opp with Vy and Hyp with V
Vy = Vsin([tex]\theta[/tex])

The x component is the same process
cos([tex]\theta[/tex]) = Vx/V

Vx = Vcos([tex]\theta[/tex])
 
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