How can I calculate heat loss in a hot water pipe system?

Click For Summary
SUMMARY

This discussion focuses on calculating heat loss in a hot water pipe system, specifically for a vertical electric hot water tank with a capacity of 120 liters. The user has modeled the tank using Joule's law, heat equations, and convection equations, and identified three types of losses: storage, distribution, and generation. Key parameters include a heating power of 3 kW, output temperatures of 60°C for cleaning and 40°C for drinking, and a cooling constant of 0.38 W/litre K day for storage losses. The user seeks detailed specifications for copper pipes to accurately calculate thermal losses during distribution.

PREREQUISITES
  • Understanding of Joule's law and heat transfer equations
  • Familiarity with thermal conductivity and its impact on heat loss
  • Knowledge of fluid dynamics, particularly flow rates in pipe systems
  • Experience with thermal resistance calculations in series
NEXT STEPS
  • Research "Thermal conductivity of copper alloys" to understand variations in pipe materials
  • Learn about "Heat loss calculations for cylindrical pipes" to refine distribution loss estimates
  • Investigate "Flow rate calculations for hot water systems" to clarify discharge rates
  • Explore "Thermal resistance in series" for more accurate energy loss modeling
USEFUL FOR

Engineers, HVAC professionals, and anyone involved in the design and optimization of hot water systems will benefit from this discussion, particularly those focusing on thermal efficiency and heat loss calculations.

wolverin
Messages
1
Reaction score
0
Hello friends,

I am into modelling of electric hot water tank which is vertical and has the capacity of 120 litres. I just assumed certain charactersitics of an existing heater so as to be more realistic in my approach. Now I am facing certain troubles in my calculations, if you know please help me out with this.

I have done the stratification of my hot water tank with the elementary equations of joules law, heat equation and convection equation so as to know how my temperature vary with stratification. I considered for my heater, a two node stratification with the heating element at the top of the tank. I frammed the equation for the two nodes and got the output for a particular power of 3kW (which is assumed from an existing 120 l heater). Now I would like to know how my output temperature will affected when there are losses.

The output temperature considered for domestic use is 60°C for cleaning purpose and 40°C for drinking and bathing purpose. So I want to frame the losses based on the fact to get this temperature at the taps after the losses has been considered.
My heating range of heater is till 65°C after that I have coded the thermostat to cut the supply.

So now let me explqin the losses:

To my knowledge there are 3 losses in a electric vertical hot water tank:
  1. Storage Losses
  2. Distribution Losses
  3. Generation Losses

So for storage losses: for an existing hot water tank of capacity 120 liters the cooling constant is 0.38 W/litre K day. So I have assumed this constant to my heater as I did not get any equation to support my inference. If you have got any idea about to calculation of storage loss that would be really helpful

Now for distribution losses:

I don't have to get through all the losses like mechanical, I am more concentrated into thermal losses affected my pipe material. I would like to know the pipe specifications used
in a 120 liters heater. SO that I can converge at an idea of framing heat loss per metre of pipe.

I have done calculations based on two formulas which I came thorough the sites that I have reffered.

The first formula I got is for a cylindrical tube of made of copper.
Input details are
Temperature of hot water at the tank : 65°C
Temperaure of Cold water: 20°C ( I have doubt in this whether I should give the outlet of the pipe, I think it is yes... It must be the outlet temperature at the pipe if so it is 60°C/40°C)

Length of the pipe assumed is 5 metres
Outer radius of pipe = 1.8 cm
Inner radius of pipe is 1.6 cm ( I would like to take more realistic values of radius for 120l I don't know whether these values will maximum accuracy in temperature at the outlet(60/40°C)

I would like to know flow through the pipe. In the brouchere of various companies it written specific discharge is for example for which I considered for 120 l it is 22litres/min. So I don't know whether it is flow rate of cold and hot water mixed or only the hot water.

and material used for the pipe is copper (pure) so the thermal conductivity of copper is found to be 400W/mK. I don't know which alloying element is used to make copper pipes. I would like to know more exact values and procedure to frame the losses for distribution.

I have also considered the fact of adopting convection and conduction by consdering thermal resistance in series so as to calculate energy lost per unit length.

So I want to know the details of the specification of pipes used in the given tank of 120 liter capacity so as to calculate the losses and flow rate .

I have missed some points I am always at your availablity

Thank you in advance
 
Engineering news on Phys.org

Similar threads

  • · Replies 15 ·
Replies
15
Views
4K
Replies
24
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 17 ·
Replies
17
Views
3K
Replies
1
Views
2K
Replies
25
Views
4K
Replies
1
Views
4K
  • · Replies 5 ·
Replies
5
Views
9K