How can I quickly integrate 6e^-2t using simple techniques?

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Homework Help Overview

The discussion revolves around the integration of the function 6e^-2t, with participants seeking clarification on the integration process and the evaluation of the integral at specific values.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants express confusion regarding the integration steps and the evaluation of the integral at given points. There are attempts to articulate the integration process and to verify calculations.

Discussion Status

The conversation includes various interpretations of the integration process, with some participants providing feedback on each other's reasoning. There is no explicit consensus on the correct approach, but multiple perspectives are being explored.

Contextual Notes

Participants are working under the assumption that they have access to calculators and are attempting to evaluate the integral at specific values of t, which may influence their understanding of the integration process.

pinkyjoshi65
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integration---very simple..need help fast!

how to integrate 6e^-2t
 
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Yes, it is very simple. What's confusing you about it, exactly?
 
dont know how to do it..lyke integal of it is 6*-0.5*e^-2t?
 
Looks right...
 
so now suppose i want to put in values for t as 0 and 6..will i get the answer as 2.99?
 
No, not at all.

Edit: No, wait, maybe. I read it wrong. I assume you know how to use a calculator, though...I don't see what you're asking help with anymore.
 
(e^-2t)/-3
 
pinkyjoshi65 said:
so now suppose i want to put in values for t as 0 and 6..will i get the answer as 2.99?

Yes you will get something like 2.99998


(e^-2t)/-3

Huh?
 
aaahhh sorryy its
-3*(e^-2t)
 
  • #10
\int 6e^{-2x}dx=6\int e^{-2x}\frac{d(-2x)}{-2}=-3\int e^{-2x}d(-2x)=-3 e^{-2x}+C
where d(-2x)=-2dx
dx=\frac{d(-2x)}{-2}
 

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