MHB How Can I Solve a Problem Using Euler's Totient Function for Odd Prime Numbers?

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To solve problems using Euler's Totient Function for odd prime numbers, it's essential to understand its definition and application. The discussion begins by examining specific examples, such as $\varphi(5)$, $\varphi(7)$, and $\varphi(11)$, to identify a general rule. For any odd prime number \( n \), the value of \( \varphi(n) \) represents the count of integers less than \( n \) that are coprime to \( n \). This foundational understanding is crucial for tackling more complex problems involving odd primes. Engaging with these examples helps clarify the function's properties and its implications.
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Hello everyone, can anybody help me with this problem?

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The solution is for all odd prime numbers, but I have no idea how to solve it.
Any help will be greatly appreciated.
 
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Hi goody,

Let's take this one step at a time by first looking at the right hand side, then the left hand side for odd primes. We will worry about the non-odd prime case later.

Let's think of some examples first. What is the value of $\varphi(5)$? How about $\varphi(7)$ and $\varphi(11)$? Can you see a general rule emerging from these examples? Now, if $n$ is an odd prime, what should the value of $\varphi(n)$ be? In other words, how many numbers less than $n$ do not share a common divisor with $n$?
 
First trick I learned this one a long time ago and have used it to entertain and amuse young kids. Ask your friend to write down a three-digit number without showing it to you. Then ask him or her to rearrange the digits to form a new three-digit number. After that, write whichever is the larger number above the other number, and then subtract the smaller from the larger, making sure that you don't see any of the numbers. Then ask the young "victim" to tell you any two of the digits of the...

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