How do I differentiate y = x^2/1-x^2 correctly?

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Homework Help Overview

The discussion revolves around the differentiation of the function y = x^2/(1-x^2), focusing on the first and second derivatives. Participants are verifying their differentiation process and results in the context of calculus.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss their differentiation attempts, specifically mentioning the use of the quotient rule. There are questions regarding the correctness of the derivatives and whether all terms have been accounted for.

Discussion Status

The conversation is ongoing, with some participants expressing uncertainty about the correctness of their derivatives. Guidance has been offered regarding the need to square the denominator, indicating a potential direction for clarification.

Contextual Notes

There is a focus on ensuring all terms are included in the differentiation process, and participants are questioning the completeness of their calculations.

Hollysmoke
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I just wanted to make sure I differentiated this correctly before I started graphing it:

y=x^2/1-x^2

y' = (2x)/(1-x^2)^2

y''=(2+6x^2)/(1-x^2)^3
 
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Hollysmoke said:
I just wanted to make sure I differentiated this correctly before I started graphing it:

y=x^2/1-x^2

y' = (2x)/(1-x^2)^2

y''=(2+6x^2)/(1-x^2)^3

I don't think that it is quite correct. I believe you are missing a term for your y' derivative (I haven't checked your y''). How did you differentiate? Using the quotient rule?
 
Yes, I used the quotient rule:

y'= (1-x^2)(2x)-(-2x)(x^2) / (1-x^2)
y'= 2x-2x^3+2x^3 / (1-x^2)
 
Don't forget to square the denominator ;)
 

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