How Do I Find the Energy of a Non-Hermitian Hamiltonian with Bosonic Operators?

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SUMMARY

The discussion focuses on calculating the energy of a non-Hermitian Hamiltonian represented by bosonic operators, specifically H=ω*(a^{dagger}a+1/2)+α*a^2+β*a^{dagger}^2. The constants ω, α, and β are real, and the energy is expressed as E=(n+1/2)*ε, where ε=ω²-4αβ. Participants highlight that the Hamiltonian is not Hermitian, which complicates the identification of eigenstates and their corresponding energies.

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  • Understanding of bosonic operators and their notation (a, a^{dagger})
  • Familiarity with Hamiltonians in quantum mechanics
  • Knowledge of eigenstates and eigenvalues in quantum systems
  • Concept of Hermitian versus non-Hermitian operators
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ozlemathph
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Hi all,

There is a Hamiltonian in terms of "a" and "a^{dagger}"bosonic operators H=ω*(a^{dagger}a+1/2)+alpha*a^2+β*a^{dagger}^2 and ω, alpha and β are real constants and its energy is E=(n+1/2)*epsilon where epsilon is ω^2-4*alpha*β. Now, I tried to find this energy but I couldn't. Would you help me please? Thanks.
 
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When you say "its energy" what do you mean specifically?

For the usual quantum harmonic oscillator, the number states |n> are eigenstates of the Hamiltonian. In this case, they are not. So what states are you trying to find the energies of?
 
ozlemathph, The first thing you might wonder about is whether your Hamiltonian is correct. It's not Hermitian!
 

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