How Do Kinetic and Potential Energy Differ in Physics?

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girlwhoneedsmathhelp
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Homework Statement
I saw this in my school textbook and have no idea how they manage to get this equation :

The context is Circular Motion :
"A particle on a string, w(angular velocity) varies throughout the motion. As you saw earlier, the value of w at any instant is given by the energy equation, which in this case is :
(1/2)m(r^2)(w^2) + mgr(1+cos(theta)) = (1/2)m(u^2) where u is the speed of the particle at the lower point."

Thank You!
Relevant Equations
1/2mv^2
mrw^2
I know that (1/2)m(u^2) is KE and initially I thought this showed PE=KE but I don't think so anymore...
I believe this has something to do with acceleration and Centripetal force but I'm so so confused
 
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I can make sense of this if the configuration is like this (##+## and ##-## represent the sign of ##\cos\theta##):
20200726_141000.jpg
 
girlwhoneedsmathhelp said:
I thought this showed PE=KE
No, it shows PE+KE=constant.
It might be clearer if we use the subscript 0 for values at the lowest point and v for the speed at any instant. So their u is my v0.
Then we have rω=v, at all times, and PE+KE=##\frac 12mr^2\omega^2 + mgr(1+\cos(\theta))=\frac 12mv^2 + mgr(1+\cos(\theta))##.
At the lowest point, ##\theta=\pi##, the PE is zero (by choice) and the KE is ##\frac 12mv_0^2##, so ##\frac 12mr^2\omega^2 + mgr(1+\cos(\theta))=\frac 12mv_0^2##.
 
Ah yes I see thank you both!
 
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