How Do Pulleys Affect Work and Energy in Lifting a Load?

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sonutulsiani
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Homework Statement




A box of mass m can be lifted using a rope and two pulleys, as shown.

http://bcs.whfreeman.com/WebPub/Physics/tiplerphysics6e_bridge/question_bank_images/6-36.png?1341

You exert a force of magnitude F on the free end of the rope. Give your answers in terms of h and w.1. Through what distance does the force move, if the load moves up a distance h?

A. 2h
B. ½h
C. h2
D. 02. How much work is done by the rope on the load, if the load is lifted at constant speed?

A. wh^2
B. 2wh
C. wh/2
D. wh3. How much work do you do on the rope?

A. wh
B. wh/2
C. 2wh
D. wh^2

Homework Equations



W= 1/2mv1^2 - 1/2mv2^2
W= F x

The Attempt at a Solution



I didn't get anything. Please help.
 
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The answer to question 1 is crucial. If you pull the rope down so that the piece on the left increases by 2 meters, the middle and right pieces together have to get shorter by 2 meters. By what length does each of these pieces alone become shorter? That is the amount by which the load rises. So what is the answer to question 1?
 
So it is 1/2 h?
 
And what about the 2nd and 3rd one? Help me with that also please.
 
Wait if the load moves up by h, then the distance by which force moves is 2h right?
 
Work = Force x distance x cos theta
 
Distance is h, theta is 0
What is force?
 
Value of cos theta which is cos 0=1
I still don't get the force.
 
Oh tension? What about it?
 
Ya so, it will be 2F - w=0
which means f=w/2

So for 2nd question, work done by rope will be F X = w/2 * 2h = wh

And 3rd question, work done by us will be = 2F * h = wh?
 
sonutulsiani said:
Ya so, it will be 2F - w=0
which means f=w/2
Yup.
So for 2nd question, work done by rope will be F X = w/2 * 2h = wh
There are two ropes, each exerting force w/2, so the rope force is 2*(w/2). Now we are told that the load moves up distance h. So work = 2*(w/2)*h=w*h, but not for the reasons you say.
And 3rd question, work done by us will be = 2F * h = wh?
Again you have a misplaced factor of 2. The force that you exert is f = w/2, but the rope on your side goes down by distance 2h. So the work done by you is work = (w/2)*2h=w*h.