How Do You Calculate the Sunset Time on the Winter Solstice at 40 Degrees North?

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SUMMARY

To calculate the sunset time on the winter solstice at 40 degrees north latitude, one must consider the sun's declination of -23.5 degrees and right ascension of 18h. The key steps involve determining the hour angle of the sun, converting local apparent solar time to mean solar time, and applying spherical trigonometry to set up the necessary calculations. A recommended resource for hand calculation methods is the book available at this link.

PREREQUISITES
  • Understanding of spherical trigonometry
  • Knowledge of solar declination and right ascension
  • Familiarity with local apparent solar time and mean solar time
  • Basic skills in astronomical calculations
NEXT STEPS
  • Study the principles of spherical trigonometry in astronomy
  • Learn how to calculate the hour angle of the sun
  • Research methods for converting local apparent solar time to mean solar time
  • Explore hand calculation techniques for solar position using recommended literature
USEFUL FOR

Astronomy students, educators, and anyone interested in calculating solar positions and understanding the mechanics of celestial events.

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Hi everyone, new member here. Anyway, for my astronomy class my professor wants us to calculate the zone time the center of the sun sets on the winter solstice, at 40 degrees north latitude, and I'm a bit stuck. I know on the winter solstice, the declination of the sun is -23.5 degrees and the right ascension is 18h, and since it would be setting the altitude would be zero. I figured out that I need to find the hour angle of the sun at that exact moment, and use this as the local apparent solar time, and correct to make it mean solar time. I think the objective is to use spherical trigonometry and set up a triangle in the sky, but I'm at a loss of how to set it up, so if anyone could give me a few pointers, that would be great. Thanks.
 
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