mathdad Messages 1,280 Reaction score 0 Thread starter May 21, 2017 #1 Factor [(a + b)^2]/4 - [a^2b^2]/9 Can someone get me started?
MarkFL Gold Member MHB Messages 13,284 Reaction score 12 May 21, 2017 #2 I would write the expression as the difference of squares: $$\frac{(a+b)^2}{4}-\frac{a^2b^2}{9}=\left(\frac{a+b}{2}\right)^2-\left(\frac{ab}{3}\right)^2$$ Or, we could write: $$\frac{(a+b)^2}{4}-\frac{a^2b^2}{9}=\frac{1}{36}\left(\left(3(a+b)\right)^2-(2ab)^2\right)$$ Now apply the difference of squares formula...:D
I would write the expression as the difference of squares: $$\frac{(a+b)^2}{4}-\frac{a^2b^2}{9}=\left(\frac{a+b}{2}\right)^2-\left(\frac{ab}{3}\right)^2$$ Or, we could write: $$\frac{(a+b)^2}{4}-\frac{a^2b^2}{9}=\frac{1}{36}\left(\left(3(a+b)\right)^2-(2ab)^2\right)$$ Now apply the difference of squares formula...:D