How Do You Solve the Inverse Function Problem Involving sin^(-1)(cos(7π/5))?

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sin-(cos(7pi/5) (arcsin)

i have the equation (x+n2pi) but don't know where to go from their
 
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f(x + P) = f(x)
the periodic function of cosine is 2pi? no?
 
Karma said:
sin-(cos(7pi/5) (arcsin)

i have the equation (x+n2pi) but don't know where to go from their
What you've written makes no sense at all! What do you mean by
"sin-(cos(7pi/5) (arcsin)"?? And what does that have to do with an inverse function?