How Do You Solve the Inverse Function Problem Involving sin^(-1)(cos(7π/5))?

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Homework Help Overview

The discussion revolves around the inverse function problem involving the expression sin^(-1)(cos(7π/5)). Participants are exploring the properties of inverse trigonometric functions and their periodicity.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • One participant attempts to express the problem using the equation (x+n2π) but is uncertain about the next steps. Another participant questions the validity of this expression and seeks clarification on its relation to inverse functions. There is also a discussion about the periodic nature of the cosine function and its implications for the problem.

Discussion Status

The discussion is ongoing, with participants questioning each other's reasoning and attempting to clarify concepts related to inverse functions and periodicity. There is no clear consensus yet, but the dialogue indicates a productive exploration of the topic.

Contextual Notes

Participants are grappling with the notation and definitions related to inverse functions, and there seems to be confusion regarding the expression used by one participant. The context of homework constraints may also influence the discussion.

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sin-(cos(7pi/5) (arcsin)

i have the equation (x+n2pi) but don't know where to go from their
 
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How did you get x+n2pi?
 
f(x + P) = f(x)
the periodic function of cosine is 2pi? no?
 
Karma said:
sin-(cos(7pi/5) (arcsin)

i have the equation (x+n2pi) but don't know where to go from their
What you've written makes no sense at all! What do you mean by
"sin-(cos(7pi/5) (arcsin)"?? And what does that have to do with an inverse function?
 

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