How Does Air Resistance Impact Force During an Egg Drop Project?

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lee132
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For an egg drop project, I have to calculate the time interval for which the force won't exceed 3 Newtons. The egg is dropped from a height of 12.19 meters, and the vehicle that carries it weights .454 kg. Calculating the force, I get .454kg*9.8 m/s^2m which equates to 4.44 Newtons. Is the 4.44 Newtons the force of the egg drop vehicle at any moment in its freefall? Because if it is, then wouldn't that mean the force could never be equal to 3 Newtons. Or is the force increasing over the time of the fall. Thanks for your help.
 
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Hi lee132! Welcome to PF! :smile:
lee132 said:
For an egg drop project, I have to calculate the time interval for which the force won't exceed 3 Newtons. The egg is dropped from a height of 12.19 meters, and the vehicle that carries it weights .454 kg. Calculating the force, I get .454kg*9.8 m/s^2m which equates to 4.44 Newtons. Is the 4.44 Newtons the force of the egg drop vehicle at any moment in its freefall? Because if it is, then wouldn't that mean the force could never be equal to 3 Newtons. Or is the force increasing over the time of the fall. Thanks for your help.

Sorry, but I don't understand the question at all …

while the vehicle is falling, there is no force between the egg and the vehicle, and the force on the vehicle (or on the egg) is, as you say, always the same. :redface:

What is the exact question? :confused: