How Does Shear Modulus Affect the Distance Traveled by a Rubber Sole?

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physics1234
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A child slides across a floor in a pair of rubber-soled shoes. The friction force acting on each foot is 25 N, the cross-sectional area of each foot is 20 cm2, and the height of the soles is 5.0 mm. Find the horizontal distance traveled by the sheared face of the sole. The shear modulus of the rubber is 3.0 x 10^6 Pa.

I used F/A=S*(deltaX/n) plugging in 20/14=3x10^6(deltaX/.5) but didn't get the right answer.
 
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physics1234 said:
A child slides across a floor in a pair of rubber-soled shoes. The friction force acting on each foot is 25 N, the cross-sectional area of each foot is 20 cm2, and the height of the soles is 5.0 mm. Find the horizontal distance traveled by the sheared face of the sole. The shear modulus of the rubber is 3.0 x 10^6 Pa.

I used F/A=S*(deltaX/n) plugging in 20/14=3x10^6(deltaX/.5) but didn't get the right answer.
I don't undersrtand where you are getting your numbers. F is 25N; A is 20cm^2; G is 3*10^6 N/m^2, and L is 5 mm.

Convert the length units to meters.

25/0.0020 = 3(10^6)x/0.005
x = 2.8*10^-5m
x = .028 mm
Hmm, seems small, better check (I don't have a good feel for pascals, having been born and bred in the USA).