How Many Ways to Color a 2x2016 Grid Using 3 Colors with Adjacency Restrictions?

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SUMMARY

The problem involves coloring a 2x2016 grid using three colors: yellow, purple, and green, with the condition that no two adjacent squares can share the same color. The solution to this combinatorial problem was successfully provided by user kaliprasad. The discussion highlights the application of graph theory principles to determine the total number of valid colorings, which is a critical aspect of solving adjacency-restricted coloring problems.

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  • Understanding of combinatorial mathematics
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  • Study the principles of graph coloring in combinatorial optimization
  • Learn about the chromatic polynomial and its applications
  • Explore adjacency restrictions in grid-based problems
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anemone
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Here is this week's POTW:

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You're required to color the squares of a $2\times 2016$ grid in 3 colors, namely yellow, purple and green. How many ways can you color the squares such that no two squares of the same color share an edge?

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Remember to read the http://www.mathhelpboards.com/showthread.php?772-Problem-of-the-Week-%28POTW%29-Procedure-and-Guidelines to find out how to http://www.mathhelpboards.com/forms.php?do=form&fid=2!
 
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Congratulations to kaliprasad for his correct solution.:)

You can find the proposed solution below:

The left-most column can be colored in $^3P_2=6$ ways. For each subsequent column, if the nth column is colored with Yellow-Purple, then the (n+1)th column can only be colored with one of Purple-Yellow, Purple-Green, Green-Yellow. That is, if we colored the first nth columns, then there are 3 ways to color the (n+1)th column. It follows that the number of ways of coloring the board is $6\times 3^{2015}$.
 

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