MHB How Many Ways to Color a 2x2016 Grid Using 3 Colors with Adjacency Restrictions?

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The problem involves coloring a 2x2016 grid using three colors—yellow, purple, and green—while ensuring that no two adjacent squares share the same color. The challenge is to determine the total number of valid color combinations under these adjacency restrictions. A solution has been provided, and kaliprasad has been recognized for submitting the correct answer. Participants are encouraged to follow the guidelines for future submissions. This problem highlights the complexities of combinatorial coloring in grid structures.
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Here is this week's POTW:

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You're required to color the squares of a $2\times 2016$ grid in 3 colors, namely yellow, purple and green. How many ways can you color the squares such that no two squares of the same color share an edge?

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Remember to read the http://www.mathhelpboards.com/showthread.php?772-Problem-of-the-Week-%28POTW%29-Procedure-and-Guidelines to find out how to http://www.mathhelpboards.com/forms.php?do=form&fid=2!
 
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Congratulations to kaliprasad for his correct solution.:)

You can find the proposed solution below:

The left-most column can be colored in $^3P_2=6$ ways. For each subsequent column, if the nth column is colored with Yellow-Purple, then the (n+1)th column can only be colored with one of Purple-Yellow, Purple-Green, Green-Yellow. That is, if we colored the first nth columns, then there are 3 ways to color the (n+1)th column. It follows that the number of ways of coloring the board is $6\times 3^{2015}$.
 
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