How Much SiCl4 Results from 2.8g of Silicon with 50% Yield?

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Discussion Overview

The discussion revolves around a homework problem involving the reaction of silicon with chlorine to produce silicon tetrachloride (SiCl4) with a specified yield of 50%. Participants are analyzing the stoichiometric calculations and the application of yield in determining the final mass of SiCl4 produced from a given mass of silicon.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant presents a calculation indicating that 2.8 g of silicon would yield 8.468 g of SiCl4 based on stoichiometric ratios.
  • Another participant challenges the initial calculation, questioning the application of the yield percentage and pointing out a potential error in the reasoning.
  • A subsequent reply clarifies that the yield percentage should be applied after calculating the stoichiometric amount of SiCl4.
  • There is a discussion about whether the final answer remains the same despite the correction in the approach to applying yield.
  • One participant confirms that the numbers appear to be correct despite the initial confusion regarding the yield application.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct application of the yield percentage in the calculations, indicating some disagreement on the methodology. However, there is general agreement that the numerical values presented are acceptable.

Contextual Notes

Participants express uncertainty regarding the correct sequence of applying stoichiometric calculations and yield percentage, highlighting potential misunderstandings in the problem-solving approach.

Who May Find This Useful

This discussion may be useful for students working on stoichiometry and yield calculations in chemistry, particularly in the context of reaction yields and conversions.

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Homework Statement


The direct reaction of silicon with Cl_2 the yield of SiCl4 is 50%. How many grams of SiCl4 are obtained in the reaction of 2.8 g of silicon with excess chlorine?


Homework Equations


Si= 28.0855g
SiCl4= 169.8963g
Si + 2Cl2 --> SiCl4


The Attempt at a Solution


2.8g Si = (84.94815 g SiCl4/28.0855 g Si)* 2.8g Si
= 8.468 g SiCl4
= 8.5 SiCl4

Could someone please let me know if I made any mistakes?
 
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a.a said:
2.8g Si = (84.94815 g SiCl4/28.0855 g Si)* 2.8g Si = 8.468 g SiCl4

This is obviously wrong - perhaps just what you wrote is wrong, as the final number looks OK. But for sure 2.8 g Si doesn't equal 8.468 g SiCl4.

However - where is the yield percentage used? Have you forgot?
 
sorri, the way i wrote is is wrong, i ment to say that 2.8 Si produces 8.468 g SiCl_4
i used the percentage yeild in that i said 84.94815 g SiCl4 rather than 169.8963g
 
Use precentage as the last step, after you calculate correct stoichiometric amount. Numbers look OK.
 
do we still arive at the same answer though?
 
Yes. That's why I wrote that numbers look OK.
 

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