How to Find Constants for the IVP Solution?

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Discussion Overview

The discussion revolves around finding constants for a specific initial-value problem (IVP) related to a differential equation. Participants explore the process of determining a particular solution from a given family of functions while addressing the relevance of the associated differential equation.

Discussion Character

  • Mathematical reasoning
  • Homework-related
  • Technical explanation

Main Points Raised

  • One participant states the general solution of the differential equation and sets up the initial conditions to find constants.
  • Another participant confirms that the first condition leads to a specific value for one of the constants, c_1, being equal to 3.
  • A participant questions the necessity of the differential equation in the context of finding the particular solution, noting that it was not used in their calculations.
  • Another participant clarifies that the differential equation is included to indicate which ODE the given solution satisfies, and discusses methods for solving the Cauchy-Euler equation.

Areas of Agreement / Disagreement

Participants generally agree on the values of the constants derived from the initial conditions, but there is some confusion regarding the relevance of the differential equation itself, indicating a lack of consensus on its necessity in the problem-solving process.

Contextual Notes

The discussion does not resolve the role of the differential equation in the context of finding the particular solution, leaving some assumptions about its relevance unaddressed.

find_the_fun
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The given family of functions is the general solution of the D.E. on the indicated interval. Find a member of the family that is a solution of the initial-value problem.

[math]y=c_1x+c_2x\ln{x}[/math] on [math](0, \infty)[/math] and [math]x^2y''-xy'+y=0[/math] and y(1)=3, y'(1)=-1

So plugging in y(1)=3 gives [math]3=c_1+c_2\ln{1}[/math] and then take the derivative to get [math]y'=c_1+c_2 \ln{x} +c_2[/math] subbing in [math]-1=C-1+c_2\ln{1}+c_2[/math]

adding 3 times the second equation to the first give [math]0=4c_1+4c_2\ln{1}+3c_2[/math]
What next?
 
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Okay, we have:

$$y(1)=c_1=3$$ (recall $\log_a(1)=0$)

$$y'(1)=c_1+c_2=-1$$

Now the system is easier to solve. :D
 
MarkFL said:
Okay, we have:

$$y(1)=c_1=3$$ (recall $\log_a(1)=0$)

$$y'(1)=c_1+c_2=-1$$

Now the system is easier to solve. :D

Ok but we never used [math]x^2y''-xy'+y=0[/math] Why was that in the question?
 
find_the_fun said:
Ok but we never used [math]x^2y''-xy'+y=0[/math] Why was that in the question?

That was to show you which ODE the given solution satisfies. You are right though, we didn't need it to find the particular solution satisfying the given conditions. The given ODE is a Cauchy-Euler equation which may be solved either by making the substitution:

$$x=e^t$$

which will given you a homogeneous equation with constant coefficients, or by assuming a solution of the form:

$$y=x^r$$

which will give you an indicial equation with a repeated root to which you may apply the method of reduction of order.
 

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