How to interpret absolute value bars?

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SUMMARY

The discussion centers on interpreting the Cauchy-Schwarz inequality, specifically the statement A·B ≤ |A·B|, where A and B are vectors. Participants clarify that the absolute value does not distribute over the inner product, and instead, |A·B| represents the absolute value of the inner product of vectors A and B. The example provided involves vectors A = {1,2} and B = {-2,3}, leading to the conclusion that |cA·B| calculates the absolute value of the inner product of the scaled vector cA and vector B.

PREREQUISITES
  • Understanding of vector operations, particularly inner products.
  • Familiarity with the Cauchy-Schwarz inequality in real inner product spaces.
  • Knowledge of vector norms and absolute values.
  • Basic proficiency in mathematical notation and vector representation.
NEXT STEPS
  • Study the properties of inner products in real vector spaces.
  • Explore the implications of the Cauchy-Schwarz inequality in various mathematical contexts.
  • Learn about vector norms and their applications in linear algebra.
  • Investigate the differences between inner products in real and complex vector spaces.
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Mathematicians, physics students, and anyone studying linear algebra or vector calculus who seeks to deepen their understanding of vector operations and inequalities.

aj-smith
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I was further looking into the Cauchy schwarz inequality and i got to a statement as follows:

A·B ≤ |A·B|

However, when I tried to prove this using numbers on paper, I wasn't sure if the absolute value bars distribute among each term, which would lead to |A|·|B|, or if the final product is then absolute.

I was wondering how you would interpret the above statement (assuming all capital letters represent vectors

These are the components I assumed.

A= {1,2} B= {-2,3} c= -2

Also how would the following below be interpreted?

|cA·B|

Thank you.
 
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aj-smith said:
I was further looking into the Cauchy schwarz inequality and i got to a statement as follows:

A·B ≤ |A·B|

*** I presume you're talking of real inner product spaces since otherwise (i.e., in a complex space) this has no meaning. ***


However, when I tried to prove this using numbers on paper, I wasn't sure if the absolute value bars distribute among each term, which would lead to |A|·|B|, or if the final product is then absolute.


*** You seemed to be using the dot \cdot to represent inner product of two vectors, so |A|\cdot |B| would be the

product of two real NUMBERS, IF by |A| you mean the norm of vector A...something completely different. ***



I was wondering how you would interpret the above statement (assuming all capital letters represent vectors

These are the components I assumed.

A= {1,2} B= {-2,3} c= -2

Also how would the following below be interpreted?

|cA·B|


*** This is the abs. value of the inner product of the vector cA by the vector B, i.e. |(-2,-4)\cdot (-2,3)|=|4-12|=8

DonAntonio


Thank you.

...
 

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