How to read a curve level accurately

  • Thread starter Thread starter Stress D.
  • Start date Start date
  • Tags Tags
    Curve
Click For Summary

Discussion Overview

The discussion revolves around the accurate reading of a curve level in a chemistry context, specifically related to the measurement of hydrochloric acid volumes in a titration experiment. Participants also explore a related question about calculating the value of x in a hydrated compound formula.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant presents a homework problem involving the measurement of hydrochloric acid volumes and asks for guidance on drawing a meniscus diagram and reading levels accurately.
  • Another participant provides a link to a resource on titration methods, potentially as a reference for the original question.
  • A participant expresses confusion about a separate question regarding the calculation of x in the formula Al2(SO4)3.K2SO4.xH2O, indicating a lack of sufficient information to solve it.
  • Further contributions inquire about the formula and molar mass of the anhydrous salt and the moles of water lost during heating, suggesting a need for additional data to proceed with calculations.
  • Participants clarify that the information provided in the original question is insufficient for determining the value of x, and one participant attempts to confirm the understanding of the molar mass of the hydrated salt.

Areas of Agreement / Disagreement

Participants generally agree that the information provided is insufficient to calculate the value of x in the hydrated compound formula. However, there is no consensus on how to proceed with the calculations due to missing data.

Contextual Notes

Limitations include the lack of complete information about the anhydrous salt's formula and molar mass, as well as the specific details needed to calculate the moles of water lost during the heating process.

Stress D.
Messages
4
Reaction score
0

Homework Statement


i got this in chemistry homework and have never done it before...

______________________________________________________________

______________________Experiment 1___Experiment 2___Experiment 3

Final volume of
hydrochloric acid/cm(3) 48.25 44.30 46.05
_______________________________________________________________

Initial volume of
hydrochloric acid/cm(3) 18.30 14.25 16.05
_______________________________________________________________

Volume of hydrochloric
acid used/cm(3) 29.95 30.05 30.00
_______________________________________________________________


Draw a diagram to show the meniscus at the top of a column of hydrochloric acid in a caliberated tube. Explain how to read the level of the acid accurately.
 
Physics news on Phys.org
tank u very much borek...am not 2 b annoyin but i have another question hear i just got to and don't no d answer to...

Calculate the value of x in the formula Al2(SO4)3.K[2]SO4.xH2O.
 
Please use plain English, you don't want to me to waste time eciphering what you mean, don't you?

You need some more information to calculate x, at the moment (just looking at the formula) it can't be done.

--
 
I am sorry i forgot about the chatting slang...

oh and i missed out this part to the question here is the whole question

Al2(SO4)3.K2SO4.xH2O -------------> Al2(SO4)3.K2SO4 + xH2O
Hydrated Anhydrous
compound compound

When 9.48g of the hydrated compound was heated at 200 degrees celsius.
5.16g of the anhydrous compound was formed.

Calculate the value of x in the formula Al2(SO4)3.K2SO4.xH2O
 
What is formula of anhydrous salt?

What is its molar mass?

How many moles of water were lost during heating?

--
methods
 
it did not give all of that information what i typed was the most info it gave...
i had to work out its relative mass = 516g
and that the reaction occurs at 200 degrees celsius and that is it
 
If I understand correctly - 516g is a molar mass of hydrated salt?

Try to follow questions I have posted earlier.

--
 

Similar threads

  • · Replies 19 ·
Replies
19
Views
10K
  • · Replies 49 ·
2
Replies
49
Views
5K
  • · Replies 17 ·
Replies
17
Views
3K
Replies
12
Views
7K
  • · Replies 7 ·
Replies
7
Views
4K